8[4-(3-3x)]+3x=3(9x+4)-4

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Solution for 8[4-(3-3x)]+3x=3(9x+4)-4 equation: 


Simplifying
8[4 + -1(3 + -3x)] + 3x = 3(9x + 4) + -4
8[4 + (3 * -1 + -3x * -1)] + 3x = 3(9x + 4) + -4
8[4 + (-3 + 3x)] + 3x = 3(9x + 4) + -4

Combine like terms: 4 + -3 = 1
8[1 + 3x] + 3x = 3(9x + 4) + -4
[1 * 8 + 3x * 8] + 3x = 3(9x + 4) + -4
[8 + 24x] + 3x = 3(9x + 4) + -4

Combine like terms: 24x + 3x = 27x
8 + 27x = 3(9x + 4) + -4

Reorder the terms:
8 + 27x = 3(4 + 9x) + -4
8 + 27x = (4 * 3 + 9x * 3) + -4
8 + 27x = (12 + 27x) + -4

Reorder the terms:
8 + 27x = 12 + -4 + 27x

Combine like terms: 12 + -4 = 8
8 + 27x = 8 + 27x

Add '-8' to each side of the equation.
8 + -8 + 27x = 8 + -8 + 27x

Combine like terms: 8 + -8 = 0
0 + 27x = 8 + -8 + 27x
27x = 8 + -8 + 27x

Combine like terms: 8 + -8 = 0
27x = 0 + 27x
27x = 27x

Add '-27x' to each side of the equation.
27x + -27x = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 27x + -27x

Combine like terms: 27x + -27x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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